xyz

I'm probably missing something obvious but here goes:

If I have a HTML checkbox field on a php form, for example:

<input type="checkbox" id="chkField" name="chkField" value="Red">Red
<input type="checkbox" id="chkField" name="chkField" value="Blue">Blue

If I select both Red and Blue, then submit my form it only seems to store the last value selected and not both.

Do I have to do something to handle this or am I missing something.

Any help appreciated.

Euge

Checkboxes are handled as arrays. Change the name attribute to "chkField[]" and see if that works.

TygerTyger

Or just give them different names, I always do because it's so much easier to keep track of. Change the IDs too, they must all have different names.

$_POST['Red'] will equal 'on' if it is checked, $_POST['Blue'] will equal 'on' if it is checked, etc. You can indulge in a bit of accessibility while you're there by using <label for="elementID"> for the labels.

__________________
Check your accessibility and web page quality

xyz

Thanks both, I have opted for Euge's suggestion (hadn't thought of the id being an array) as I am dynamically generating a form and therefore do not know how many fields of checkbox type there will be.

One further question if I may. So I know have the following:

<input type="checkbox" id="chkField[]" name="chkField[]" value="Red">Red
<input type="checkbox" id="chkField[]" name="chkField[]" value="Blue">Blue

and using the following PHP to retrieve the checkbox values from my array:

while ( list ( $key, $val ) = @each ( $chkField )) {
echo $val;
}

THIS WORKS FINE - because $chkField is an array

However, the field ID (id="chkField[]") is being generated dynamically from an array of fields - $v_FIELD_LIST and I am therefore looping through these fields, creating the fields within a foreach loop:

foreach ($v_FIELD_LIST as $value) {

}

so where $value will have the field name, it is not an array and therefore:

while ( list ( $key, $val ) = @each ( $value )) {
echo $val;
}

DOESN'T WORK

My question is: how do I reference my array of chkField and not the field name chkField.

Hope this makes sense.

Simon

If I understand correctly you should be able to substitute @each ( $value ) with

notice the double dollar..

__________________
Freelance PHP Programming
__________________

xyz

Simon, Excellent, that's exactly it.

Thanks.