PHP includes going wrong.

goodyear · 25th July 2003, 02:41 PM

Hi

I'm trying to include a php file into another one, and it just won't do it. I do this all the time, and I can't see what's wrong. The file that does the including runs:

PHP Code:

  <?php

 
require_once('wrapper.php') or die("Cannot open wrapper file.");

 
print_header("home");

 
?>

<p>The Home Page</p>

 
<?php

 
print_footer();

 
?>

And the error it throws is:

Quote:

Warning: main(1): failed to open stream: No such file or directory in /home/virtual/site**/fst/var/www/html/church/index.php on line 3

Fatal error: main(): Failed opening required '1' (include_path='.:/php/includes:/usr/share/php') in /home/virtual/site**/fst/var/www/html/church/index.php on line 3

(** edited becasue I'm paranoid!)

Now, wrapper.php is in the same directory as index.php.

So what gives?

Goodyear

goodyear · 25th July 2003, 02:55 PM

Okay, took out the or die() construct, and it worked.

Was there something wrong with my syntax, there?

Christopher · 25th July 2003, 08:18 PM

I don't think the include() functions (including require, require_once() and include_once()) return a value. So you were testing a null value. At the bottom of your included file you could add "return true;" to make it work.

Looks like that to me anyway, but I don't see why that would prevent the inclusion of the file... Was the file still included, just with the error message?

goodyear · 26th July 2003, 12:13 AM

Nah. Wasn't included - it couldn't find the file. Very, very strange. Still, it's working now.

leafish_paul · 27th July 2003, 04:48 PM

From what I can gather from the PHP manual, both 'require' and 'require_once' statements throw a fatal error and halt the execution of the script if the file isn't found anyway, so there is no need for an '...or die...' statement.

goodyear · 27th July 2003, 04:55 PM

Yeah, that's the way it's working now.
Thanks.